# All from 9 and the Last from 10 (Part IV)

In last week’s issue of this newsletter, we discussed cases where the numbers of digits in the subtrahend is less than the number of zeroes in the minuend. This week we will take on cases where the subtrahend ends in zero or zeroes.

Here, we cannot immediately apply “All from 9 and the last from 10” because taking away zero from 10 will give 10 as the units’ digit.

What we do is to 1) momentarily disregard the ending zero or zeroes; 2) apply “All from 9 and the last from 10 to the remaining digits of the subtrahend and 3) add back the remaining zeroes at the end.

Example: 10,000 – 6,700 = ?

- Momentarily disregard the two zeroes in the subtrahend
- Apply “all from 9 and the last from 10” to 67 to get 33
- Add back the two zeroes to have a final answer of 3,300

Example: P1,000.00 – 470.00 = ?

- Disregard the 3 ending zeroes ( two after the decimal point)
- Apply Nikhilam to 47 and get 53
- Add back “0.00” to have a final result of P530.00

Try these:

- 100 – 30 =
- 1000 – 400 =
- 1000 – 540 =
- 10,000 – 3,450 =
- 10,000 – 7,200 =
- 100, 000 – 27,000 =
- 100,000 – 53, 230 =
- 1,000,000 – 325, 000 =
- 1,000,000 – 645, 200 =
- 1,000,000 – 165,430 =

Answers to last issue’s exercises:

- P100.00 – 3.45 = P96.55
- P100.00 – 7. 82 = P 92.18
- P1000.00 – 32.54 = P 967.46
- P1000.00 – 75.68 = P924.32
- 100,000 – 376 = 99,624
- 1,000,000 – 7634 = 992,366
- P500.00 – 97.65 = P 402.35
- 300,000 – 234 = 299,766
- 7,000,000 – 4,567 = 6,995,433
- 23,000,000 – 17,257 = 22,982,743