Math Education

Last week I mentioned about the YouTube video about this problem which is said to be a Math Olympiad problem. The solution offered was also to use the difference of two squares formula: 2^18 – 1 = (2^9 + 1)(…

Two weeks ago, I found YouTube videos discussing this problem and a similar one which is said to be a Math Olympiad problem, “20^18 – 1”. The approach to solving the problems, as shown in both videos, are basically the…

This question was given In the intermediate category of the 2nd Philippine National Vedic Math Olympiad last 2021 were participants are required to answer 50 questions in 1 hour. Since all the choices are whole numbers, we can assume that…

What this question given in the primary category of the 1st International Vedic Mathematics Olympiad in September 11, 2021 really requires is to find out the square root of of 5625. Anyone who is familiar with Vedic Mathematics can answer…

Our previous Math Tip deals with recognizing numbers divisible by 11. The next logical lesson should be how to determine the remainder when a number is divided by 11. This is the subject of this question, which was given the…

A number is divisible by 11 if the alternating sum of the digits is 0 or a multiple of 11. This also means that the difference between the sum of the odd-placed digits and the sum of the even-placed digits…

In our previous posts we discussed short methods of multiplying number pairs having identical starting digits and their “final digits add up to 10”. We first applied it to squaring numbers ending in 5 (5 + 5 = 10) and…

In our previous posts we discussed short methods of multiplying number pairs having identical starting digits and their “final digits add up to 10”. We first applied it to squaring numbers ending in 5 (5 + 5 = 10) and…

Last week we discussed squaring numbers ending in 5. The technique used the Vedic Mathematics Sutra, By One More the One Before. This is possible because it uses another VM Sub-Sutra, When the Final Digits Add Up to 10, since…